nasa announces discovery of dark

L. Riofrio said...

".... making "dark energy" unnecessary.

I am all for making the dark energy unnecessary. However there

may be a more physical or "close to experience" way of getting

rid of it.

For instance consider the role that the formidable pressure

found at the center of a star might play in gravitational

phenomena. A simple formula for that pressure is given by

g*rho*r where g is the surface gravity, rho the mean density

and r is the radius of the star. Imagine a star that is divided

up into two hemispheres--a day side hemisphere and a night side

hemisphere. Assume further that because of the Tully Fisher law

and my experiments (to find out more click my name), the day

side surface gravity is slightly less than the night side

surface gravity and that this difference is equal to A the

centripetal acceleration of the star around the galactic

center.

If this is the case then formula for the force of the day side

hemisphere on the night side one, would then given by

(A-g)*rho*r*(pi*r^2). Here (pi*r^2) is the cross sectional area

of the star. The force of the night side hemisphere on the day

side one would be given by g*rho*r*(pi*r^2). Subtracting the

two forces, the net force that would then centripetally

accelerate the star towards the galactic center would be

A*rho*pi*r^3.

If the star is located in the "Newtonian regime" of the galaxy,

the Newtonian expression for that force that would

centripetally accelerate the star towards the galactic center

would be GMm/r^2.

This can be written as A*m where A = GM/r^2. Expanding the mass

part of this expression it becomes A*rho*4/3*pi*r^3. Thus when

compared to A*rho*pi*r^3 it can be seen that the two

expressions only differ by a factor of 4/3. This slight

difference between the two expressions should not be a problem

because it was assumed that rho as a function of r is constant

and we know in practice it is not. Here we have almost two

equivalent formulas. The old tried and true one that does not

work well beyond the solar system or the one that requires

luminosity to have a slight attractive power?

This is taking too long. If you want to know how the near

equivalence of the two above expression coupled with the

coincidence of the dimming and acceleration of the universe can

get rid of the dark energy click my name.

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